Q 1 a) If the length of a rectangle is twice its breadth. Compute its area, if its breadth is taken as x cm b) If now, the length is four times the breadth. Compute the new Area. c) Compare, by finding the ratio of the original area to the new Area. d) What do you observe in comparing the two Areas.
Answer:
a) 2x² cm²
b) 4x² cm²
c)1:2
d) The new area is double the original area.
Step-by-step explanation:
a) Given breadth = x cm
Also, given Length is twice the breadth.
Therefore, Length = 2x
So, Area = Length x Breadth = 2x x x cm² = 2x² cm²
b) This time length is four times the breadth x cm.
Therefore, Length = 4x cm
So, Area = 4x x x cm² = 4x² cm²
c) Original Area = 2x² cm²
New Area = 4x² cm²
Therefore, the ratio of Original to New Area is
2x² : 4x² = 1:2
d) Clearly, from ratio we can see that new area is double the original area.