The exterior angle of a regular polygon is 2x, and the interior angle is 4x.Find the measure of one interior and exterior angle. About the author Jade
Answer: Answer: \huge\star \underline{ \boxed{ \purple{Answer}}}\star⋆Answer⋆ \frac{1}{x\:+\:4}\:+\:\frac{1}{2}\:=\:\frac{1}{x\:+\:4}x+41+21=x+41 \frac{2\:+\:(x\:+\:4)}{2(x\:+\:4}\:=\:\frac{1}{x\:+\:4}2(x+42+(x+4)=x+41 \frac{6\:+\:x}{2x\:+\:8}\:=\:\frac{1}{x\:+\:4}2x+86+x=x+41 \red{On\:cross\:multiplying\:=}Oncrossmultiplying= (6\:+\:x)(x\:+\:4)\:=\:2x\:+\:8(6+x)(x+4)=2x+8 \blue{Opening\:brakets\:=}Openingbrakets= 6x\:+24\:+\:x^{2}\:+\:4x\:=\:2x\:+\:86x+24+x2+4x=2x+8 x^{2}\:+\:10x\:+\:24\:=\:2x\:+\:8×2+10x+24=2x+8 x^{2}\:+\:10x\:-\:2x+\:24\:-\:8\:=\:0x2+10x−2x+24−8=0 x^{2}\:+\:8x\:+\:16\:=\:0x2+8x+16=0 x^{2}\:+\:4x\:+\:4x\:+\:16\:=\:0x2+4x+4x+16=0 x(x\:+\:4)\:+\:4(x\:+\:4)\:=\:0x(x+4)+4(x+4)=0 (x\:+\:4)\:+\:(x\:+\:4)\:=\:0(x+4)+(x+4)=0 \green{Therefore\:,}Therefore, x\:=\:-4\:,\:-4x=−4,−4 -4\:=\:\green{non\:extraneous\:variable}−4=nonextraneousvariable Step-by-step explanation: \huge\mathcal\pink{Hope \: it \: helps \: you}Hopeithelpsyou \huge\mathcal\pink{friend}friend Reply
Answer:
Answer:
\huge\star \underline{ \boxed{ \purple{Answer}}}\star⋆Answer⋆
\frac{1}{x\:+\:4}\:+\:\frac{1}{2}\:=\:\frac{1}{x\:+\:4}x+41+21=x+41
\frac{2\:+\:(x\:+\:4)}{2(x\:+\:4}\:=\:\frac{1}{x\:+\:4}2(x+42+(x+4)=x+41
\frac{6\:+\:x}{2x\:+\:8}\:=\:\frac{1}{x\:+\:4}2x+86+x=x+41
\red{On\:cross\:multiplying\:=}Oncrossmultiplying=
(6\:+\:x)(x\:+\:4)\:=\:2x\:+\:8(6+x)(x+4)=2x+8
\blue{Opening\:brakets\:=}Openingbrakets=
6x\:+24\:+\:x^{2}\:+\:4x\:=\:2x\:+\:86x+24+x2+4x=2x+8
x^{2}\:+\:10x\:+\:24\:=\:2x\:+\:8×2+10x+24=2x+8
x^{2}\:+\:10x\:-\:2x+\:24\:-\:8\:=\:0x2+10x−2x+24−8=0
x^{2}\:+\:8x\:+\:16\:=\:0x2+8x+16=0
x^{2}\:+\:4x\:+\:4x\:+\:16\:=\:0x2+4x+4x+16=0
x(x\:+\:4)\:+\:4(x\:+\:4)\:=\:0x(x+4)+4(x+4)=0
(x\:+\:4)\:+\:(x\:+\:4)\:=\:0(x+4)+(x+4)=0
\green{Therefore\:,}Therefore,
x\:=\:-4\:,\:-4x=−4,−4
-4\:=\:\green{non\:extraneous\:variable}−4=nonextraneousvariable
Step-by-step explanation:
\huge\mathcal\pink{Hope \: it \: helps \: you}Hopeithelpsyou
\huge\mathcal\pink{friend}friend