The unit place digit in 2^50 x 5^48 – 9 is tennetiraj please help for my questions About the author Savannah
Step-by-step explanation: Given :– 2^50 x 5^48 – 9 To find :– The unit place digit in 2^50 x 5^48 – 9 ? Solution :– Given number is 2^50 x 5^48 – 9 2^50 = 2×2×2×…×(50 times) 2^1 = 2 2^2 = 4 2^3 = 8 2^4 = 16 2^5 = 32 2^6 = 64… If you continues the unit places are 2,4,8,6.They repeat agin again 2^50 = (2^5)^10 The units place of 2^50 = 4 and 5^48 5^1 = 5 5^2 = 25 We continue like this we get always 5 in its units place => The unit digit in 5^48 is 5 Now The unit place of 2^50×5^48 is => 4×5 => 20 Unit place is 0 and given that The unit place of 2^50 x 5^48 – 9 We have 0 as units place of the product and 9 is subtracted from the product So The required digit must be 10-9 = 1 Answer:– The unit place for the given problem is 1 Reply
Step-by-step explanation:
Given :–
2^50 x 5^48 – 9
To find :–
The unit place digit in 2^50 x 5^48 – 9 ?
Solution :–
Given number is 2^50 x 5^48 – 9
2^50 = 2×2×2×…×(50 times)
2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64…
If you continues the unit places are 2,4,8,6.They repeat agin again
2^50 = (2^5)^10
The units place of 2^50 = 4
and 5^48
5^1 = 5
5^2 = 25
We continue like this we get always 5 in its units place
=> The unit digit in 5^48 is 5
Now
The unit place of 2^50×5^48 is
=> 4×5
=> 20
Unit place is 0
and given that
The unit place of 2^50 x 5^48 – 9
We have 0 as units place of the product and
9 is subtracted from the product
So The required digit must be 10-9 = 1
Answer:–
The unit place for the given problem is 1
Answer:
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