A man bought two computers for 45000thousands .He sold one at a loss of 5% and another at profit of 5%.if the selling price of eac

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1. Answer:

   Given :

   A man bought two computers for rs 45000. he sold one at a loss of 5% and other at a profit of 5%. The selling price of each set is the same.

   To find :

   find the cost price of each set.

   Solution :

   Let the cost price of one computer be x

   The second computer be ( 45000-x)

   Selling price :

   he sold one at a loss of 5%:

   100 – 5 = 95.

   Loss on CP = 95x/100

   He sold others at a profit of 5%:

   100 + 5 = 105

   Profit on CP = (45000-x)*105/100

   Cost Price :

   Given : Selling price is same for each computer:

   => 95x/100 = (45000-x)*105/100

   => 95x/100 = (45000 * 105)/100 – 105x/100

   => 95x/100 = 47250 – 105x/100

   => 95x/100 + 105x/100 = 47250

   => 200x/100 = 47250

   => 2x = 47250

   => x = 47250/2

   => x = 23625

   So, the cost of first computer is Rs 23,625

   The cost of second computer is 45000 – 23625 = Rs 21,375.

   Step-by-step explanation:

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