The tops of two poles of height 20m and 14m are connected by a wire if the wire makes an angle of 30⁰ with origin till then the length of the wire is About the author Emery
Given : The tops of two poles of height 20m and 14m are connected by a wire. The wire makes an angle of 30 degrees with horizontal To find: the length of the wire Solution: Height of one pole = 20 m Height of another pole = 14 m Height of bigger pole above the top of Smaller pole = 20 – 14 = 6 m Let sat length of the wire = L m the wire makes an angle of 30 degrees with horizontal, => Sin 30° = 6 /L => 1/2 = 6/L => L = 12 Length of Wire = 12 m Reply
Answer: correct answer is Step-by-step explanation: Given that : Heights of two poles are 20 and 14m respectively. Angle wire makes with horizontal =30∘ Let distance between two poles be x and length of wire be y tan30∘=x20−14=x6 31=x6 ⇒x=63 As length of the wire will form the hypotenuse of right angled triangle thus formed, y2=62+(63)2=144 ∴y=12 m Reply
Given : The tops of two poles of height 20m and 14m are connected by a wire. The wire makes an angle of 30 degrees with horizontal
To find: the length of the wire
Solution:
Height of one pole = 20 m
Height of another pole = 14 m
Height of bigger pole above the top of Smaller pole = 20 – 14 = 6 m
Let sat length of the wire = L m
the wire makes an angle of 30 degrees with horizontal,
=> Sin 30° = 6 /L
=> 1/2 = 6/L
=> L = 12
Length of Wire = 12 m
Answer:
correct answer is
Step-by-step explanation:
Given that : Heights of two poles are 20 and 14m respectively.
Angle wire makes with horizontal =30∘
Let distance between two poles be x and length of wire be y
tan30∘=x20−14=x6
31=x6
⇒x=63
As length of the wire will form the hypotenuse of right angled triangle thus formed,
y2=62+(63)2=144
∴y=12 m