The diagonal of a rectangular field is 60m more than the shorter side. Find the sides of

the field.​

The diagonal of a rectangular field is 60m more than the shorter side. Find the sides of

the field.​

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  1. Answer:

    We have,

    Long side of rectangular field is 60 meters more then the shorter side.

    Let the longer side will be (y+30)mtr.

    And the length of the diagonal will be (y+60) mtr.

    Now, According to given question.

    Using Pythagoras theorem,

    (Diagonal)

    2

    =(shorterside)

    2

    +(longerside)

    2

    (y+60)

    2

    =y

    2

    +(y+30)

    2

    ⇒y

    2

    +3600+120y=y

    2

    +y

    2

    +900+60y

    ⇒3600+120y−y

    2

    −900−60y=0

    ⇒−y

    2

    +60y+2700=0

    ⇒y

    2

    −60y−2700=0

    ⇒y

    2

    −(90−30)y−2700=0

    ⇒y

    2

    −90y+30y−2700=0

    ⇒y(y−90)+30(y−90)=0

    ⇒(y−90)(y+30)=0

    If,

    y+30=0

    y=−30(notpossible)

    If,

    y−90=0

    y=90

    So, the length of shorter side =y−30=90−39=60

    Longer side 90+30=120

    Hence, this is the answer.

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