2x^3-x^2+3x+1p(x)i)p(-1)=2(-1)^3-(-1)^2+3(-1)+1=2*-1-1+(-3)+1=-2-1-3+1=-5ii)p(1)=2(1)^3-(1)^2+3*1+1=2*1-1+3+1=2-1+3+1=5iii)p(2)=2(2)^3-(2)^2+3*2+1=2*8-4+6+1=16-4+6+1=19So, p(-1)+p(1)-p(2)=-5+5-19=-19 Ans.Mark as brainliest Reply
p(x)=2x³-x²+3x+1 p(-1)=2(-1)³-(-1)²+3(-1)+1 =-2-1-3+1 = -5 p(1)=2(1)³-(1)²+3(1)+1 =2-1+3+1 =5 p(2)=2(2)³-(2)²+3(2)+1 =16-4+6+1 =19 p(-1)+p(1)-p(2) -5+5+19 =19 Reply
2x^3-x^2+3x+1
p(x)
i)p(-1)=2(-1)^3-(-1)^2+3(-1)+1
=2*-1-1+(-3)+1
=-2-1-3+1
=-5
ii)p(1)=2(1)^3-(1)^2+3*1+1
=2*1-1+3+1
=2-1+3+1
=5
iii)p(2)=2(2)^3-(2)^2+3*2+1
=2*8-4+6+1
=16-4+6+1
=19
So, p(-1)+p(1)-p(2)
=-5+5-19
=-19 Ans.
Mark as brainliest
p(x)=2x³-x²+3x+1
p(-1)=2(-1)³-(-1)²+3(-1)+1
=-2-1-3+1
= -5
p(1)=2(1)³-(1)²+3(1)+1
=2-1+3+1
=5
p(2)=2(2)³-(2)²+3(2)+1
=16-4+6+1
=19
p(-1)+p(1)-p(2)
-5+5+19
=19