8Rahul horrowed & 1, 200 from his friend at thegate of 12% pa find the amount to be paid atthe end of 3 years About the author Hailey

We have Principal as ₹1200 and Rate of 12% and time taken for borrow is 3 years. we know that: [tex] \circ \ {\purple{\underline{\boxed{\sf{ Interest_{(Simple)} = \dfrac{PRT}{100} }}}}} \\ \\ \\ \colon\implies{\sf{ \dfrac{12 \cancel{00} \times 12 \times 3}{ \cancel{100} } }} \\ \\ \\ \colon\implies{\sf{ 12 \times 12 \times 3 }} \\ \\ \\ \colon\implies{\sf{ Rs. \ 432 }} \\ [/tex] ~Now, we’ve to find the Amount paid after 3 years as:- [tex] \circ \ {\red{\underline{\boxed{\sf{ Amount = Principal+Interest }}}}} \\ \\ \colon\mapsto{\sf{ 1200 + 432 }} \\ \\ \colon\mapsto{\sf{ Rs. \ 1632 }} [/tex] Hence, Rahul has to paid ₹ 1632 at the end of the 3rd year. More to Know Simple Interest for n months = (P × n × R)/ (12 ×100) To calculate the SI for a certain amount of money (P), rate of interest (R) and time (T), the formula is: SI = (PTR)/100 Reply

We have

Principal as ₹1200andRate of 12%andtime taken for borrow is 3 years.we know that:

[tex] \circ \ {\purple{\underline{\boxed{\sf{ Interest_{(Simple)} = \dfrac{PRT}{100} }}}}} \\ \\ \\ \colon\implies{\sf{ \dfrac{12 \cancel{00} \times 12 \times 3}{ \cancel{100} } }} \\ \\ \\ \colon\implies{\sf{ 12 \times 12 \times 3 }} \\ \\ \\ \colon\implies{\sf{ Rs. \ 432 }} \\ [/tex]

~Now, we’ve to find the

Amount paid after 3 yearsas:-[tex] \circ \ {\red{\underline{\boxed{\sf{ Amount = Principal+Interest }}}}} \\ \\ \colon\mapsto{\sf{ 1200 + 432 }} \\ \\ \colon\mapsto{\sf{ Rs. \ 1632 }} [/tex]

Hence,

Rahul has to paidat the end of the 3rd year.

₹1632MoretoKnow