7. To convert rupees and paise into paise, we need to convert rupeesinto paise and —-the paise. About the author Anna
Answer: hope it helps ☺️ Step-by-step explanation: Substitutex=cos\alp,\alp∈[0:;π] \displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+ 1−x 2 ∣= 2 (2x 2 −1)\Leftright∣cos\alp+sin\alp∣= 2 (2cos 2 \alp−1) \displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N 2 cos(\alp− 4 π )∣=N 2 cos(2\alp)\Right\alp∈[0; 4 π ]∪[ 4 3π ;π] 1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0; 4 π ] \displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp− 4 π )=cos(2\alp)… 2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[ 4 3π ;π] \displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp− 4 π )=cos(2\alp)… 1 hope it helps ☺️ Reply
Answer:
hope it helps ☺️
Step-by-step explanation:
Substitutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+
1−x
2
∣=
2
(2x
2
−1)\Leftright∣cos\alp+sin\alp∣=
2
(2cos
2
\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N
2
cos(\alp−
4
π
)∣=N
2
cos(2\alp)\Right\alp∈[0;
4
π
]∪[
4
3π
;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;
4
π
]
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−
4
π
)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[
4
3π
;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−
4
π
)=cos(2\alp)…
1
hope it helps ☺️
Answer:
100 is answer of question