7. Find the area of a right triangle whose base is 1.2 m and hypotenuse 3.7 m.

7. Find the area of a right triangle whose base is 1.2 m and hypotenuse 3.7 m.

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2 thoughts on “<br />7. Find the area of a right triangle whose base is 1.2 m and hypotenuse 3.7 m.<br />​”

  1. Answer:

    • Area of a right triangle is 2.1 m².

    Step-by-step explanation:

    Given that:

    • Base of a right triangle = 1.2 m
    • Hypotenuse of a right triangle = 3.7 m

    To Find:

    • Area of a right triangle.

    First finding the height of a right triangle:

    By pythagoras theorem.

    ⟶ H² = P² + B²

    ⟶ (3.7)² = P² + (1.2)²

    ⟶ 13.69 = P² + 1.44

    ⟶ P² = 13.69 – 1.44

    ⟶ P² = 12.25

    ⟶ P = √12.25

    ⟶ P = 3.5

    ∴ Perpendicular/Height of a right triangle = 3.5 m

    Finding the area of a right triangle:

    ⇒ Area = (B × P)/2

    ⇒ Area = (1.2 × 3.5)/2

    ⇒ Area = 2.1

    ∴ Area of a right triangle = 2.1 m²

    Some abbreviations used are:

    • H = Hypotenuse
    • P = Perpendicular/Height
    • B = Base
    Reply
  2. ꧁༺Answer ༻꧂

    we know that:

    Area of right angle triangle = 1/2 * Base * perpendicular height

    And

    According to Pythagoras theorem

    (Hypotenuse)² = (Base)² + (perpendicular)²

    Here,

    Base = 1.2 m

    Hypotenuse = 3.7 m

    => Perpendicular = √(H² – B²)

    = √ (3.7² – 1.2²)

    = √ (13.69 – 1.44)

    = √ 12.25

    = 3.5 m

    Now,

    => Area = 1/2 * B * P

    = 1/2 * 1.2 * 3.5

    = 1/2 * 4.2

    = 2.1 m²

    Reply

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