6. The centre of a cirde is 42). If one end of the diameter of the circle is (-3. 7) then
find the other end.​

1 thought on “6. The centre of a cirde is 42). If one end of the diameter of the circle is (-3. 7) then<br />find the other end.​”

1. Step-by-step explanation:

   [tex]{\underline{\boxed{ \purple{ \maltese \: {\textsf{\textbf{\purple{question}}}}}}}} [/tex]

   6. The centre of a cirde is 42). If one end of the diameter of the circle is (-3. 7) then

   find the other end.

   [tex]{\underline{\boxed{ \purple{ \maltese \: {\textsf{\textbf{\purple{solution \: }}}}}}}} [/tex]

   The other end is (-5,-3).

   Since we have given that

   Centre of circle = (-4,2)

   One end of diameter of circle = (-3,7)

   Let the other end of circle be (x,y).

   As we know that centre is the mid point of diameter.

   So, it becomes,

   [tex] \frac{ – 3 + x}{2} \: \frac{7 + y}{2} = (- 4 \: – 2)[/tex]

   Cᴏᴍᴘᴀʀɪɴɢ ʙᴏᴛʜ ᴛʜᴇ Tᴇʀᴍs,

   [tex] \frac{ – 3 + x}{2} = – 4[/tex]

   [tex] – 3 + x = – 8[/tex]

   [tex]x = – 8 + 3 \\ = – 5[/tex]

   Sɪᴍɪʟᴀʀʟʏ,

   [tex] \frac{7 + 4}{2} = 2[/tex]

   [tex]7 + y = 4[/tex]

   [tex]y = 4 – 7 \\ = – 3[/tex]

   Sᴏ, Tʜᴇ Oᴛʜᴇʀ Eɴᴅ ᴡɪʟʟ ʙᴇ (-5,-3)

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   Hᴏᴘᴇ ɪᴛ Hᴇʟᴘs ʏᴜ!

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