6) For equation
5x+3y +11=0 and 2x+4y =-10
find D?​

2 thoughts on “6) For equation<br />5x+3y +11=0 and 2x+4y =-10<br />find D?​”

1. ____________________

   ♧Question♧

   • For equation
   • 5x+3y +11=0 and 2x+4y =-10
   • find D.

   ♧Answer♧

   Let the D = ( x , y )

   • ➠5x + 3y + 11 = 0.
   • ➠5x + 3y = -11. e.q 1
   • ➠2x + 4y = -10. e.q 2

   ☆Now multiply the equation 1 with 2

   • ➠5x + 3y = -11
   • ➠2(5x + 3y = -11)
   • ➠10x + 6y = -22 e.q 3

   ☆Now multiply equation 2 with 5

   • ➠2x + 4y = -10
   • ➠5(2x + 4y = -10)
   • ➠10x + 20y = -50. e.q 4

   ☆Now subtracting e.q 3 and e.q 4

   • ➠(10x + 20y = -50) – (10x + 6y = -22)
   • ➠-14y = 28
   • ➠y = -12/-28
   • ➠y = -2

   ☆Now put the value of y in e.q 1.

   • ➠5x + 3y = -11.
   • ➠5x + 3(-2) = -11
   • ➠5x – 6 = -11
   • ➠5x = – 11 + 6
   • ➠5x = – 5
   • ➠x = -5/5
   • ➠x = -1

   ☆So the value of is D = ( -1 , -2 ).

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2. Answer:

   5 3

   2. 4

   = (5×4)-(2×3)

   D = 20-6

   D = 14

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