6.Find the value (s) of k for which the givenquadratic equations has real and equal roots:kx (x – 2√5)+ 10 = 0 About the author Sarah

Answer: kx(x-2sq.root 5) +10 = 0 kx2-2sq.root5 kx +10 = 0 b2 -4ac = (-2 sq.root 5k)2 -4(k)(10) >0 = 20k2 -40k >0 4 k(5k-10) >0 20k(k-2)>0 k>0 , k>2 Reply

Answer:kx(x-2sq.root 5) +10 = 0

kx2-2sq.root5 kx +10 = 0

b2 -4ac = (-2 sq.root 5k)2 -4(k)(10) >0

= 20k2 -40k >0

4 k(5k-10) >0

20k(k-2)>0

k>0 , k>2