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6.
A goes 10km distance with average speed of 6km/h while rest 20km he travels with an
average speed of 15 km/h. Then th

By Nevaeh

6.
A goes 10km distance with average speed of 6km/h while rest 20km he travels with an
average speed of 15 km/h. Then the average speed of ‘A’ during the whole journey =
1) 10km/h 2) 12km/h
3) 13 km/h
4) 14.5km/h​

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Nevaeh

Find the value by using Suito ble property
45×352 + 352×55​

(i) What do you mean by homologous series? Explain with alkane series.
(ii) Define heterocyclic compound with example
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1 thought on “6.<br />A goes 10km distance with average speed of 6km/h while rest 20km he travels with an<br />average speed of 15 km/h. Then th”

  1. Answer:

    distanceS1=10km,speed v1=6km/hr

    time taken T1=v1S=610=1.67hr

    distanceS2=20km,speed v2=15km/hr

    time taken T2=v2S=1520=1.33hr

    total time taken T=T1+T2=1.67+1.33=3hr

    average speed=total time taken/total distance travelled=330

    =10km/hr

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