56 gm of CaO react with 63 gm of HNO3 mass of Ca(NO3)2 formed will be?​

1 thought on “56 gm of CaO react with 63 gm of HNO3 mass of Ca(NO3)2 formed will be?​”

1. CaO + 2HNO₃ —-> Ca(NO₃)₂ + H₂O

   Molar Mass:

   CaO = (40+16) g = 56 g

   2HNO₃ = 2*(1+14+48) g = 126 g

   Ca(NO₃)₂ = 40+2*(14+48) g = 164 g

   H₂O = (2+16) g = 18 g

   This means 126 g of Nitric Acid has been taken to produce 164 g of Calcium Nitrate.

   So, 63 g of Nitric Acid will produce = (164/126)*63 g of Calcium Nitrate

   = 82 g of Calcium Nitrate

   I hope this helps.

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