Answer: let alpha be -3 and beta be -5 Step-by-step explanation: alpha + beta = -3+ -5 =-3 -5 = -8 alpha × beta = -3 ×-5 = -15 therefore, the quadratic equation = x^-(alpha+ beta)x + alpha×beta =0 = X^- (-8)x +(-15)=0 x^+8x-15=0 Reply
Answer: xsquare +8x +15 Step-by-step explanation: sum of zeroes= -8 product=15 equation with zeroes as -5 and -8 =k(x square – sum(x)+ product)=0 k is any non zero natural number 0=x square +8x+15 if k=1 Reply
Answer:
let alpha be -3 and beta be -5
Step-by-step explanation:
alpha + beta = -3+ -5
=-3 -5
= -8
alpha × beta = -3 ×-5
= -15
therefore, the quadratic equation
= x^-(alpha+ beta)x + alpha×beta =0
= X^- (-8)x +(-15)=0
x^+8x-15=0
Answer:
xsquare +8x +15
Step-by-step explanation:
sum of zeroes= -8
product=15
equation with zeroes as -5 and -8
=k(x square – sum(x)+ product)=0
k is any non zero natural number
0=x square +8x+15 if k=1