5. There are 20 cylindrical pillars in a building, each having a diameter of50 cm and height 4 m. Find the cost of cleaning them at 14 per m^2 About the author Bella
Answer: Rs 1760 Step-by-step explanation: Radius of 1 pillar = 50/2 cm = 25 cm = 0.25 m Curved surface of 1 pillar is 2πrh = 2 x (22/7) x (0.25) x 4 m² = 44/7 m² ∴ Curved surface area of 20 such pillars 20 x 44/7 m² = 880/7 m² Cost of cleaning = rate x area = Rs 14 x (880/7) = Rs 1760 Reply
____________________________________ Given :- Radius of 1 pillar = 50/2 cm ⟹ 25 cm = 0.25 m Curved surface of 1 pillar is 2πrh ⟹ 2 x (22/7) x (0.25) x 4 m² ⟹ 44/7 m² Therefore, Curved surface area of 20 such pillars 20 x 44/7 m² = 880/7 m². ____________________________________ Answer :- Cost of cleaning = rate x area ⟹ Rs 14 x (880/7) ⟹ Rs 1760 ____________________________________ [tex] [/tex] Reply
Answer:
Rs 1760
Step-by-step explanation:
Radius of 1 pillar = 50/2 cm
= 25 cm = 0.25 m
Curved surface of 1 pillar is 2πrh
= 2 x (22/7) x (0.25) x 4 m²
= 44/7 m²
∴ Curved surface area of 20 such pillars 20 x 44/7 m² = 880/7 m²
Cost of cleaning = rate x area
= Rs 14 x (880/7)
= Rs 1760
____________________________________
Given :-
⟹ 25 cm = 0.25 m
⟹ 2 x (22/7) x (0.25) x 4 m²
⟹ 44/7 m²
Therefore, Curved surface area of 20 such pillars 20 x 44/7 m² = 880/7 m².
____________________________________
Answer :-
⟹ Rs 14 x (880/7)
⟹ Rs 1760
____________________________________
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