5x+2y=13 2x+6y=26 Elimination method. What is the value of X? What is the value of Y? About the author Rose

Answer: x = 1 & y = 4 Step-by-step explanation: let 5x + 2y = 13, be equation 1 and 2x + 6y = 26, be equation 2 * multiplying equation 1 by 3 to make the coefficients of y be equal. [ 5x + 2y = 13 ][3] ⇒ 15x + 6y = 39 finding the value of x [ 15x + 6y ] – [ 2x + 6y ] = 39 – 26 [ 15x – 2x ] + [ 6y – 6y ] = 13 13x = 13 x = 13/13 x = 1 putting the value of x in equation 1 5x + 2y = 13 ⇒5[1] + 2y = 13 5 + 2y = 13 2y = 13 – 5 2y = 8 y = 8/2 y = 4 ∴ The value of x = 1 & y = 4 “f.o.l.l.o.w me for more answer like this” Reply

Step-by-step explanation: 5x+2y=13 (i) 2x+6y=26 (ii) multiply equation ( 1 )by 2 and equation (11) by 5 2×(5x+2y)=2×13 5×(2x+6y)=5×26 10x+4y=26 (iii) 10x+30y= 130(iv) sub equation (iii) from equation (iv) -26y=-104 y=-104/-26 y=4 now put the value of y in equation (ii) 2x+6×4=26 2x+24=26 2x=26-24 2x=2 x=2/2 x=1 Reply

Answer:x = 1 & y = 4Step-by-step explanation:let 5x + 2y = 13, be equation 1 and 2x + 6y = 26, be equation 2

* multiplying equation 1 by 3 to make the coefficients of y be equal.[ 5x + 2y = 13 ][3]

⇒

15x + 6y = 39finding the value of x[ 15x + 6y ] – [ 2x + 6y ] = 39 – 26

[ 15x – 2x ] + [ 6y – 6y ] = 13

13x = 13

x = 13/13

x = 1putting the value of x in equation 15x + 2y = 13⇒5[1] + 2y = 13

5 + 2y = 13

2y = 13 – 5

2y = 8

y = 8/2

y = 4∴ The value of x = 1 & y = 4“f.o.l.l.o.w me for more answer like this”Step-by-step explanation:5x+2y=13 (i)

2x+6y=26 (ii)

multiply equation ( 1 )by 2 and equation (11) by 5

2×(5x+2y)=2×13

5×(2x+6y)=5×26

10x+4y=26 (iii)

10x+30y= 130(iv)

sub equation (iii) from equation (iv)

-26y=-104

y=-104/-26

y=4

now put the value of y in equation (ii)

2x+6×4=26

2x+24=26

2x=26-24

2x=2

x=2/2

x=1