5x+2y=13

2x+6y=26

Elimination method. What is the value of X? What is the value of Y?

2 thoughts on “5x+2y=13<br /><br /> 2x+6y=26<br /><br /> Elimination method. What is the value of X? What is the value of Y?”

1. Answer:

   x = 1 & y = 4

   Step-by-step explanation:

   let 5x + 2y = 13, be equation 1 and 2x + 6y = 26, be equation 2

   * multiplying equation 1 by 3 to make the coefficients of y be equal.

   [ 5x + 2y = 13 ][3]

   ⇒ 15x + 6y = 39

   finding the value of x

   [ 15x + 6y ] – [ 2x + 6y ] = 39 – 26

   [ 15x – 2x ] + [ 6y – 6y ] = 13

   13x = 13

   x = 13/13

   x = 1

   putting the value of x in equation 1

   5x + 2y = 13

   ⇒5[1] + 2y = 13

   5 + 2y = 13

   2y = 13 – 5

   2y = 8

   y = 8/2

   y = 4

   ∴ The value of x = 1 & y = 4

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2. Step-by-step explanation:

   5x+2y=13 (i)

   2x+6y=26 (ii)

   multiply equation ( 1 )by 2 and equation (11) by 5

   2×(5x+2y)=2×13

   5×(2x+6y)=5×26

   10x+4y=26 (iii)

   10x+30y= 130(iv)

   sub equation (iii) from equation (iv)

   -26y=-104

   y=-104/-26

   y=4

   now put the value of y in equation (ii)

   2x+6×4=26

   2x+24=26

   2x=26-24

   2x=2

   x=2/2

   x=1

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