# 5x+2y=13 2x+6y=26 Elimination method. What is the value of X? What is the value of Y?

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5x+2y=13

2x+6y=26

Elimination method. What is the value of X? What is the value of Y?

### 2 thoughts on “5x+2y=13<br /><br /> 2x+6y=26<br /><br /> Elimination method. What is the value of X? What is the value of Y?”

x = 1 & y = 4

Step-by-step explanation:

let 5x + 2y = 13, be equation 1 and 2x + 6y = 26, be equation 2

* multiplying equation 1 by 3 to make the coefficients of y be equal.

[ 5x + 2y = 13 ][3]

15x + 6y = 39

finding the value of x

[ 15x + 6y ] – [ 2x + 6y ] = 39 – 26

[ 15x – 2x ] + [ 6y – 6y ] = 13

13x = 13

x = 13/13

x = 1

putting the value of x in equation 1

5x + 2y = 13

⇒5[1] + 2y = 13

5 + 2y = 13

2y = 13 – 5

2y = 8

y = 8/2

y = 4

∴ The value of x = 1 & y = 4

“f.o.l.l.o.w me for more answer like this”

2. Step-by-step explanation:

5x+2y=13 (i)

2x+6y=26 (ii)

multiply equation ( 1 )by 2 and equation (11) by 5

2×(5x+2y)=2×13

5×(2x+6y)=5×26

10x+4y=26 (iii)

10x+30y= 130(iv)

sub equation (iii) from equation (iv)

-26y=-104

y=-104/-26

y=4

now put the value of y in equation (ii)

2x+6×4=26

2x+24=26

2x=26-24

2x=2

x=2/2

x=1