4. Suppose we represent the distance above the ground by a positive integer and that below the ground by a negative integer then, answer the following:
(1) An elevator descends into a mine shaft at the rate of 6 metres per minute. What will be its position after 30 minutes?
(ii) If it begins to decend from 24 metres above the ground, what will be its position after 80 minutes
Answer:
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Answer:
Starting position of mine shaft is = 10m above ground
but,
it moves in opposite direction so it travels the distance (-350 m ) below the ground.
Total distance covered by mine shaft = 10m – (-350m)
= 10 + 350
= 360m
Now, taken to cover a distance of 6m by it = 1 minute
Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min
6
1
min
Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \
6
1
× 360 = 60 min
60 minutes = 1 hour
thus, in one hour the mine shraft reaches = 350 below the ground.
Step-by-step explanation:
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