Answer: Solution. – 2 can be written as – 20 10 and 0 as 0 10 . Thus we have – 19 10 , – 18 10 , – 17 10 , – 16 10 , – 15 10 , … … … . . , – 1 10 between – 2 and 0. Reply
Step-by-step explanation: Acceleration is change in velocity per unit time a= (t 2 −t 1 ) (v 2 −v 1 ) v 2 −v 1 =30kmph= 30×(5/18)m/s = 3 25 m/s t 2 −t 1 =10s a= (3×10)hi ok na 25 = 6 5 m/s 2 Reply
Answer:
Solution. – 2 can be written as – 20 10 and 0 as 0 10 . Thus we have – 19 10 , – 18 10 , – 17 10 , – 16 10 , – 15 10 , … … … . . , – 1 10 between – 2 and 0.
Step-by-step explanation:
Acceleration is change in velocity per unit time
a=
(t
2
−t
1
)
(v
2
−v
1
)
v
2
−v
1
=30kmph= 30×(5/18)m/s
=
3
25
m/s
t
2
−t
1
=10s
a=
(3×10)hi ok na
25
=
6
5
m/s
2