4) If A(1, 3) & B(2, 1) are points, find the equation of the focus of point P such
that PA = PB
(a) 2x + 4y – 5 = 0<

4) If A(1, 3) & B(2, 1) are points, find the equation of the focus of point P such
that PA = PB
(a) 2x + 4y – 5 = 0
(c) 2x – 4y + 5 = 0
(b) 2x – 4y – 5 = 0
(d) 2x + 4y + 5 = 0

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  1. Answer:

    C. 2x-4y+5=0

    Step-by-step explanation:

    Here PA=PB

    PA²=PB²

    (X1-X2)²+(Y1-Y2)²=(X1-X2)²+(Y1-Y2)²

    (1-X)²+(3-Y)²=(2-X)²+(1-Y)²

    (1-2X+X²)+(9-6Y+Y²)=(4-4X+X²)+(1-2Y+Y²)

    1-2X+X²+9-6Y+Y²=4-4X+X²+1-2Y+Y²

    10-2X-6Y=5-4X-2Y

    10-5= -4X+2X-2Y+6Y

    5= -2X+4Y

    -2X+4Y-5=0

    taking out subtraction sign common

    2x-4y+5=0

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