4. Find P(0), P(1) and P(2) for the polynomial

P(t) = 2 + t + 2t square – t cube

# 4. Find P(0), P(1) and P(2) for the polynomial

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Given⇒p(t)=2+t+2t²-t³

To Find The value at⇒p(0) , p(1) and (2)

Now take⇒p(t)=2+t+2t²-t³

When P(0)⇒P(0) = 2 + 0 + 2(0)t² – (0)³

⇒p(0) = 2

WhenP(1)⇒P(1) = 2 + 1 + 2(1)²-(1)³

⇒P(1) = 3 + 2 – 1

⇒P(1) = 5 – 1

⇒P(1) = 4

When P(2)⇒P(2) = 2 + 2 + 2(2)² – (2)³

⇒p(2) = 4 + 2×4 – 8

⇒P(2) = 4 + 8 – 8

⇒P(2) = 4

Answer⇒P(0) = 2 , P(1) = 4 And P(2) = 4

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