4. Find P(0), P(1) and P(2) for the polynomial
P(t) = 2 + t + 2t square – t cube​

2 thoughts on “4. Find P(0), P(1) and P(2) for the polynomial<br />P(t) = 2 + t + 2t square – t cube​”

1. Given

   ⇒p(t)=2+t+2t²-t³

   To Find The value at

   ⇒p(0) , p(1) and (2)

   Now take

   ⇒p(t)=2+t+2t²-t³

   When P(0)

   ⇒P(0) = 2 + 0 + 2(0)t² – (0)³

   ⇒p(0) = 2

   WhenP(1)

   ⇒P(1) = 2 + 1 + 2(1)²-(1)³

   ⇒P(1) = 3 + 2 – 1

   ⇒P(1) = 5 – 1

   ⇒P(1) = 4

   When P(2)

   ⇒P(2) = 2 + 2 + 2(2)² – (2)³

   ⇒p(2) = 4 + 2×4 – 8

   ⇒P(2) = 4 + 8 – 8

   ⇒P(2) = 4

   Answer

   ⇒P(0) = 2 , P(1) = 4 And P(2) = 4

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2. Answer............???

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