Hello , dear friend. here is Ur solution.._______★ Sol. [tex]39 {y}^{3} (50 {y}^{2} – 98) \: divide \: \: by \: \: 26 {y}^{2} (5y + 7)3[/tex] _________________________________ [tex]= > 50 {y}^{2} – 98 = 2(25 {y}^{2} – 49)[/tex] [tex]\begin{gathered} = > \frac{39 {y}^{3}(50 {y}^{2} – 98) }{26 {y}^{2}(5y + 7) } \\ \\ = > \frac{3 \times 13 \times y \times y \times y \times 2 \times (5y – 7) \times (5y + 7)}{2 \times 13 \times y \times y \times (5y + 7)} \\ \\ = > \frac{3 \times y \times (5y – 7)}{1} \end{gathered}[/tex] Hope it’s helps you. ☺☺☺☺ Reply
Hello , dear friend.
here is Ur solution.._______★
Sol.
[tex]39 {y}^{3} (50 {y}^{2} – 98) \: divide \: \: by \: \: 26 {y}^{2} (5y + 7)3[/tex]
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[tex]= > 50 {y}^{2} – 98 = 2(25 {y}^{2} – 49)[/tex]
[tex]\begin{gathered} = > \frac{39 {y}^{3}(50 {y}^{2} – 98) }{26 {y}^{2}(5y + 7) } \\ \\ = > \frac{3 \times 13 \times y \times y \times y \times 2 \times (5y – 7) \times (5y + 7)}{2 \times 13 \times y \times y \times (5y + 7)} \\ \\ = > \frac{3 \times y \times (5y – 7)}{1} \end{gathered}[/tex]
Hope it’s helps you.
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