37. The number x is exactly divisible by 5 and the
remainder obtained on dividing the number y by 5
is 1. What remainder

37. The number x is exactly divisible by 5 and the
remainder obtained on dividing the number y by 5
is 1. What remainder will be obtained when (x +
y) is divided by 5?
(a) (b) 1 (c)2
(d) 3​

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2 thoughts on “37. The number x is exactly divisible by 5 and the<br />remainder obtained on dividing the number y by 5<br />is 1. What remainder”

  1. Answer:

    Let x/5 = p and let y when divided by 5 gives q as quotient and 1 as remainder.

    Then, y = 5q + 1

    Now x = 5p and y = 5q + 1

    ∴ x + y = 5p + 5q + 1 = 5(p + q) + 1

    So, required remainder = 1

    Step-by-step explanation:

    so the answer is 1

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