3) verify a ÷(b÷c)(a÷b)+(a÷b) for the followingValues of a,b and c: (a) a= 12, b= -2, c= 3 About the author Melody
Hola Mate!! Let put the value of a,b and c in equation => 12 ÷ (-2÷3) [12÷(-2)] ÷ [12÷(-2)] => 12 ÷ (-2/3) (-6) ÷ (-6) => 12 × (-3/2) × (-6) ÷ (-6) => [6×(-3)] × (-6) + (-6) => (-18) × (-6) + (-6) => 108 + (-6) => 108 – 6 => 102 Hopes its help u ❤❤❤❤ Reply
Answer: let put the value of a, b and c in equation = 12÷( -2÷3) ( 12÷ -2) + ( 12÷ -2) = 12÷ ( -2/3) ( -6) + ( -6) = 12 ÷ -2/3 × (-6) + (-6) = (12× -3/2) × (-6) +(-6) = ( 6× -3 ) × (-6) + (-6) = (-18) × (-6) + (-6) = 108 + (-6) = 108 – 6 = 102 I hope it’s help you please mark me as brainlist. ” keep learning dear friend ” Reply
Hola Mate!!
Let put the value of a,b and c in equation
=> 12 ÷ (-2÷3) [12÷(-2)] ÷ [12÷(-2)]
=> 12 ÷ (-2/3) (-6) ÷ (-6)
=> 12 × (-3/2) × (-6) ÷ (-6)
=> [6×(-3)] × (-6) + (-6)
=> (-18) × (-6) + (-6)
=> 108 + (-6)
=> 108 – 6
=> 102
Hopes its help u ❤❤❤❤
Answer:
let put the value of a, b and c in equation
= 12÷( -2÷3) ( 12÷ -2) + ( 12÷ -2)
= 12÷ ( -2/3) ( -6) + ( -6)
= 12 ÷ -2/3 × (-6) + (-6)
= (12× -3/2) × (-6) +(-6)
= ( 6× -3 ) × (-6) + (-6)
= (-18) × (-6) + (-6)
= 108 + (-6)
= 108 – 6
= 102
I hope it’s help you please mark me as brainlist.
” keep learning dear friend ”