3) The angles of triangle are (x-40)º, (x-20)° and [ 1/2 x-10]
Find the value of x.​

2 thoughts on “3) The angles of triangle are (x-40)º, (x-20)° and [ 1/2 x-10]<br />Find the value of x.​”

1. Answer:

   • The value of x is 100.

   Step-by-step explanation:

   Given that:

   The angles of triangle.

   1. First angle = (x – 40)°
   2. Second angle = (x – 20)°
   3. Third angle = (½x – 10)°

   To Find:

   • The value of x.

   We know that:

   • Sum of angles of a triangle is equal to 180°.

   Finding the value of x:

   According to the question.

   ⟶ (x – 40) + (x – 20) + (½x – 10) = 180

   ⟶ x – 40 + x – 20 + ½x – 10 = 180

   ⟶ x + x + ½x – 40 – 20 – 10 = 180

   ⟶ 2½x – 70 = 180

   ⟶ 2½x = 180 + 70

   ⟶ 2½x = 250

   ⟶ (5/2)x = 250

   ⟶ x = (250 × 2)/5

   ⟶ x = 500/5

   ⟶ x = 100

   ∴ The value of x = 100

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2. Sum of all angles of a triangle is [tex]\bold\orange{180°}[/tex]

   Solution

   First angle[tex]\bold\red{x=40°}[/tex]

   Second angle [tex]\bold\blue{x=-20°}[/tex]

   Third angle [tex]\bold\pink{x/2-10}[/tex]

   First angle+second angle+third angle=180°

   [tex]\bold\green{(x-40°)+(x-20°)+(x-x/2-10)=180°}[/tex]

   [tex]\bold\orange{x+x+x/2-10)-(40+20+10)=180°}[/tex]

   [tex]\bold\purple{5x/2=250°}[/tex]

   [tex]\bold{x=100°}[/tex]

   Reply