3 bodies with masses 3kg, 6kg, and 2kg are pushed with 49.5N. Find acceleration and contact force.

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Answer:   For all three parts, use Newton's second law, F = ma.    (a) The total mass of the system is    m = m1+m2+m3 = 12.5 kg + 24.7 kg + 31.0 kg = 68.2 kg    so the acceleration is    a = T1/m = (64.0 N) / (68.2 kg) = 0.938 m/s2.    (b) T1 = m1a = (12.5 kg)(0.938 m/s2) = 11.7 N    (c) T2 = (m1+m2)a = (12.5 kg + 24.7 kg)(0.938 m/s2)        = (37.2 kg)(0.938 m/s2) = 34.9 N   Step-by-step explanation:   hope it is helpful for you and please mark me brainiest please

Ariana

10. Which terms of the G.P. 2, 8, 32, —- is 1, 31,072 ?
5th. term b) 9th term c) 12th. term d) 6th. term
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