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3. A shopkeeper has 120 kg of rice. In the first four weeks of a month, he sells 20 kg. 10 kg, 15.4 kg
and 25 kg respectively

By Margaret

3. A shopkeeper has 120 kg of rice. In the first four weeks of a month, he sells 20 kg. 10 kg, 15.4 kg
and 25 kg respectively. Find the quantity of rice remaining after the end of four weeks. .
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Margaret

identify the line of symmetry and order of rotation for the following figure​

Find u and v using cross-multiplication method-
u + 3v = 2
3u + (2/3)*v = 1

2 thoughts on “3. A shopkeeper has 120 kg of rice. In the first four weeks of a month, he sells 20 kg. 10 kg, 15.4 kg<br />and 25 kg respectively”

  1. Answer:

    Step-by-step explanation:

    let the remaining rice be x

    X+20+10+15.4+25 = 120

    X+70.4 = 120

    x= 120-70.4

    x= 49.6 kgs

    ∴ 49.6 kgs of rice is left at the end of four weeks

    Reply

  2. Answer:

    Hi mate.

    Step-by-step explanation:

    The shopkeeper has 120kg rice.

    Total weight he sells = 20 + 10 + 15.4 + 25 = 70.4

    So the quantity of rice remaining = 120 – 70.4 = 49.6

    So there is 49.6kg rice remaining

    Reply

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