2y²+3y-2=0. Solve this problem by middle term splitting method​

2y²+3y-2=0. Solve this problem by middle term splitting method​

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2 thoughts on “2y²+3y-2=0. Solve this problem by middle term splitting method​”

  1. Answer:

    Given: 2y²+3y-2=0

    To find: The zeroes of the equation by middle term splitting

    Proof:

    = 2y²+3y-2=0

    ⇒ 2y²+3y-2=0

    ⇒ 2y²+4y-y-2=0

    ⇒ 2y²+4y-y-2=0

    ⇒ 2y(y+2) -1 (y +2) =0

    ⇒ (2y-1) (y+2) =0

    ⇒ (2y-1) = 0 or (y+2) =0

    ⇒ 2y= 1 or (y+2) =0

    ⇒ y= [tex]\frac{1}{2}[/tex] or y = -2

    Hence, y= [tex]\frac{1}{2}[/tex] or y = -2

    Hope you got that.

    Thank You.

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  2. Answer:

    y=-2 or y=½

    Step-by-step explanation:

    2y²+3y-2=0

    2y²+4y-1y-2=0

    2y(y+2)-1(y+2)=0

    (y+2) (2y-1)=0

    y=-2 or y=½

    this is the ans

    tried it yay

    Reply

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