25. Two angles of triangle are equal and the third angle is greater than each of these angles by 30°
Find all the angles of t

2 thoughts on “25. Two angles of triangle are equal and the third angle is greater than each of these angles by 30°<br />Find all the angles of t”

1. Given:

   • Two angles of triangle are equal
   • The third angle is greater than each of these angles by 30°.

   To Find:

   • Measure of all the angles of the triangle.

   Solution:

   Let,

   The Two Angles be x°,x°.

   Then, The Third Angle is (x+30°)

   According To Sum

   [tex]→\;{\bf{x+x+(x+30°) = 180°}}[/tex]

   ❂ Sum Of All The Angles Of A Triangle Are 180°.

   [tex]→\;{\bf{3x = 180°-30°}}[/tex]

   [tex]→\;{\bf{x = \cancel{\frac{150°}{3}}}}[/tex]

   [tex]→\;{\bf{x = 50°}}[/tex]

   Third Angle ☞ x+30° = 50°+30° → 80°

   AnSweR:

   Measure of Two Equal Angles ◕➜ [tex]\Large{\red{\mathfrak{50°}}}[/tex]

   Measure of The Third Angle ◕➜ [tex]\Large{\green{\mathfrak{80°}}}[/tex]

   Hope It Helps You ✌️

   Reply

2. I think 75°

   Step-by-step explanation:

   because, if one angle is equal to 30° and the 2 angles equal then, a triangle is 180° then 30°-180° is equal to 75°

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