24. किसी कार्यालय में कर्मचारियों का औसत वेतन 1800 रु. है। पाँच कर्मचारियों की नियुक्ति
के बाद कुल वेतन 4000 रु० बढ़ गया तथा

1 thought on “24. किसी कार्यालय में कर्मचारियों का औसत वेतन 1800 रु. है। पाँच कर्मचारियों की नियुक्ति<br />के बाद कुल वेतन 4000 रु० बढ़ गया तथा”

1. Answer:

   In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)

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