20) Name the type of quadrilateral formed by ABCD in
fig 1.0
Fig 1.0​

20) Name the type of quadrilateral formed by ABCD in
fig 1.0
Fig 1.0​

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Melanie

1 thought on “20) Name the type of quadrilateral formed by ABCD in<br />fig 1.0<br />Fig 1.0​”

  1. Step-by-step explanation:

    (i) Let the given points are A(−1,−2), B(1,0), C(−1,2)and D(−3,0) Then,

    AB=

    (1+1)

    2

    +(0+2)

    2

    =

    2

    2

    +2

    2

    =

    4+4

    =

    8

    BC=

    (−1−1)

    2

    +(2−0)

    2

    =

    (2

    2

    +2

    2

    )

    =

    4+4

    =

    8

    CD=

    ((−3)−(−1))

    2

    +(0−2)

    2

    =

    2

    2

    +(−2)

    2

    =

    4+4

    =

    8

    DA=

    (−3)−(−1))

    2

    +(0−(−2))

    2

    =

    (−2)

    2

    +2

    2

    =

    4+4

    =

    8

    AC

    ((−1)−(−1))

    2

    +(2−(−2))

    2

    =

    0+4

    2

    =

    16

    =4

    BD=

    (−3−1)

    2

    +(0−0)

    2

    =

    −4

    2

    =

    16

    =4

    Since the four sides AB,BC,CD and DA are equal and the diagonals AC and BD are equal .

    ∴ Quadrilateral ABCD is a square.

    (ii)Let the given points are A(−3,5),B(3,1),C(0,3) and D(−1,−4)Then

    AB=

    (−3−3)

    2

    +(5−1)

    2

    =

    (−6)

    2

    +4

    2

    =

    36+16

    =

    52

    BC=

    (3−0)

    2

    +(1−3)

    2

    =

    (3

    2

    +(−2)2

    2

    )

    =

    9+4

    =

    11

    CD=

    (0−(−1))

    2

    +(3−(−4))

    2

    =

    1

    2

    +(7)

    2

    =

    1+49

    =

    50

    DA=

    (−1)−(−3))

    2

    +((−4)−5))

    2

    =

    (2)

    2

    +(−9)

    2

    =

    4+81

    =

    85

    Here AB

    =BC

    =CD

    =DA

    ∴ it is a quadrilateral.

    (iii)Let the given points are A(4,5),B(7,6),C(4,3) and D(1,2)Then

    AB=

    (7−4)

    2

    +(6−5)

    2

    =

    3

    2

    +1

    2

    =

    9+1

    =

    10

    BC=

    (4−7)

    2

    +(3−6)

    2

    =

    ((−3)

    2

    +(−3)

    2

    )

    =

    9+9

    =

    18

    CD=

    (1−4)

    2

    +(2−3)

    2

    =

    (−3)

    2

    +(−1)

    2

    =

    9+1

    =

    10

    DA=

    (1−4)

    2

    +(2−5)

    2

    =

    (−3)

    2

    +(−3)

    2

    =

    9+9

    =

    18

    AC

    (4−4)

    2

    +(3−5)

    2

    =

    0+(−2)

    2

    =

    4

    =2

    BD=

    (1−7)

    2

    +(2−6)

    2

    =

    (−6)

    2

    +(−4)

    2

    =

    36+16

    =

    52

    Here AB=CD,BC=DA . But AC

    =BD

    Hence the pairs of opposite sides are equal but diagonal are not equal so it is a parallelogram.

    hope it helps

    pls mark as brainliest

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