1 thought on “2)<br />Which of the following is a quadratic equation?<br />(A) 11=5x²+x3 (B) 3y/4=2/y+7 (C) 4x²+3vx-2=0 (D) y(y+2)=y?+3y”
Solution :–
Quadratic equation is a equation whose highest power of degree is 2 and the general form of quadratic equation is ax^2 + bx + c = 0 where a, b and c are integers and x ≠ 0
Now,
Let’s check one by one
a) 11 = 5x^2 + x^3
x^3 + 5x^2 -11 = 0
Here , Highest power of degree is 3 .
Therefore, It is not a quadratic equation
b) 3y/4 = 2/y + 7
3y/4 – 2/y = 7
3y^2 – 2/4y = 7
3y^2 – 2 = 7 * 4y
3y^2 – 2 = 28y
3y^2 – 28y -2 = 0
Here, Highest power of degree is 2
Hence, It is a quadratic equation and it also satisfy general form ax^2 + bx + c
c) 4x^2 + 3vx – 2 = 0
Here, you can observe that it contains different variables and also not satisfying general form ax^2 + bx + c
d) y( y + 2 ) = y^2 + 3y
y^2 + 2y = y^2 + 3y
y^2 – y^2 = 3y – 2y
0 = y
Here, the value of variable y is 0 but in a quadratic equation variables ≠ 0
Solution :–
Quadratic equation is a equation whose highest power of degree is 2 and the general form of quadratic equation is ax^2 + bx + c = 0 where a, b and c are integers and x ≠ 0
Now,
Let’s check one by one
a) 11 = 5x^2 + x^3
x^3 + 5x^2 -11 = 0
Here , Highest power of degree is 3 .
Therefore, It is not a quadratic equation
b) 3y/4 = 2/y + 7
3y/4 – 2/y = 7
3y^2 – 2/4y = 7
3y^2 – 2 = 7 * 4y
3y^2 – 2 = 28y
3y^2 – 28y -2 = 0
Here, Highest power of degree is 2
Hence, It is a quadratic equation and it also satisfy general form ax^2 + bx + c
c) 4x^2 + 3vx – 2 = 0
Here, you can observe that it contains different variables and also not satisfying general form ax^2 + bx + c
d) y( y + 2 ) = y^2 + 3y
y^2 + 2y = y^2 + 3y
y^2 – y^2 = 3y – 2y
0 = y
Here, the value of variable y is 0 but in a quadratic equation variables ≠ 0
Hence, Option B is your answer mate[tex].[/tex]