2Q.3Find the third side of the triangle if its perimeter is 7p’q+13r.14r2p²q – 4r About the author Rose
Answer: Step-by-step explanation: Given, Perimeter of a triangle = 7p 2 −5p+11 And, two of its sides are p 2 +2p−1 and 3p 2 −6p+3 We know that, Perimeter of a triangle = Sum of three sides of triangle ⇒ 7p 2 −5p+11=(p 2 +2p−1)+(3p 2 −6p+3)+( Third side of triangle) 7p 2 −5p+11=(4p 2 −4p+2)+( Third side of triangle) ⇒ Third side of triangle=(7p 2 −5p+11)−(4p 2 −4p+2) = (7p 2 −4p 2 )+(−5p+4p)+(11−2) = 3p 2 −p+9 Thus, the third side of the triangle is 3p 2 −p+9 Reply
Answer:
Step-by-step explanation:
Given,
Perimeter of a triangle = 7p
2
−5p+11
And, two of its sides are p
2
+2p−1 and 3p
2
−6p+3
We know that,
Perimeter of a triangle = Sum of three sides of triangle
⇒ 7p
2
−5p+11=(p
2
+2p−1)+(3p
2
−6p+3)+( Third side of triangle) 7p
2
−5p+11=(4p
2
−4p+2)+( Third side of triangle)
⇒ Third side of triangle=(7p
2
−5p+11)−(4p
2
−4p+2)
= (7p
2
−4p
2
)+(−5p+4p)+(11−2)
= 3p
2
−p+9
Thus, the third side of the triangle is 3p
2
−p+9