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Paul reaches office from home 12 before, if he goes at a speed of 15 kmph. He reaches office 20
minutes late if he tra

By Isabella

2
Paul reaches office from home 12 before, if he goes at a speed of 15 kmph. He reaches office 20
minutes late if he travels at a speed of 9 kmph. Find the distance between his office to home?​

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Isabella

Money is an example of

(a) Bank

(b) R.BI (c) Formal source of credit (d) Informal source of credit​

Compound A dissolved in water gives compound B, which is used in white washing. Compound B reacts with CO2 to form a white PPT of

1 thought on “2<br />Paul reaches office from home 12 before, if he goes at a speed of 15 kmph. He reaches office 20<br />minutes late if he tra”

  1. Step-by-step explanation:

    To find the distance,

    Let distance = x km.

    Time taken at 3 kmph : dist/speed = x/3 = 30 min late.

    time taken at 4 kmph : x/4 = 40 min earlier

    difference between time taken : 40-(-30) = 70 mins = 70/60 hours.

    x/3- x/4 = 70/60

    x/12 = 7/6

    x = 14 km.

    So option B is the correct answer.

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