Answer: Step-by-step explanation: f length of a diagonal of a square is 12√2 cm. Let the length of each of that square be a cm. From the properties of square we know that the sides( adjacent ) of square intersect each other at 90°. Thus, by Pythagoras theorem : – = > side^2 + side^2 = diagonal^2 = > ( a cm )^2 + ( a cm )^2 = ( 12√2 cm )^2 [ since length of diagonal is 12√2 cm ] = > a^2 cm^2 + a^2 cm^2 = 144 x 2 cm^2 = > 2a^2 cm^2 = 144 x 2 x cm^2 = > a^2 = 144 = > a^2 = 12^2 = > a = 12 Hence the required length of each side of square is 12 cm. From the properties of square : – Perimeter of square = 4 x square Therefore, = > Perimeter of this square = 4 x 12 cm = > Perimeter of this square = 48 cm Hence the required perimeter of this square is 48 cm. Reply
Answer:
Step-by-step explanation:
f length of a diagonal of a square is 12√2 cm.
Let the length of each of that square be a cm. From the properties of square we know that the sides( adjacent ) of square intersect each other at 90°.
Thus, by Pythagoras theorem : –
= > side^2 + side^2 = diagonal^2
= > ( a cm )^2 + ( a cm )^2 = ( 12√2 cm )^2
[ since length of diagonal is 12√2 cm ]
= > a^2 cm^2 + a^2 cm^2 = 144 x 2 cm^2
= > 2a^2 cm^2 = 144 x 2 x cm^2
= > a^2 = 144
= > a^2 = 12^2
= > a = 12
Hence the required length of each side of square is 12 cm.
From the properties of square : –
Perimeter of square = 4 x square
Therefore,
= > Perimeter of this square = 4 x 12 cm
= > Perimeter of this square = 48 cm
Hence the required perimeter of this square is 48 cm.
Answer:
by my point of view
Step-by-step explanation:
s×s
22✓2×22✓2
484✓2 is the answer