2) If
1
then find the value of
4x-y
4x+y
​

1 thought on “2) If<br />1<br />then find the value of<br />4x-y<br />4x+y<br />​”

1. Answer:

   In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC) In the given figure, EB  AC, BG  AE and CF  AE. Prove that  ABG   DCB. A

   11. In the given figure, medians AD and BE of AABC meet at G

   and DF | BE.

   Prove that (i) EF = FC (ii) AG : GD = 2 : 1.

   (Hint. angleEBC – angleFDC)

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