2. Find the number of sides of a polygon ifthe sum of the interior angles isa) 10 right anglesb) 720°d) 540°c) 1620° About the author Ella
Answer: a) 7 b) 6 c) 5 d) 11 Step-by-step explanation: a) 10 right angles = 900 degree sum of interior angles of a polygon =(n-2)*180 where n is the number of sides 900=(n-2)*180 n-2=900/180=5 n=7 b) applying the same formula, (n-2)*180=720 n-2=720/180=4 n=6 c) again (n-2)*180=540 n-2=540/180=3 n=5 d) (n-2)*180=1620 n-2=1620/180=9 n=11 n is the number of sides in each case, hence the answer Reply
Answer:
a) 7
b) 6
c) 5
d) 11
Step-by-step explanation:
a) 10 right angles = 900 degree
sum of interior angles of a polygon =(n-2)*180
where n is the number of sides
900=(n-2)*180
n-2=900/180=5
n=7
b)
applying the same formula,
(n-2)*180=720
n-2=720/180=4
n=6
c)
again (n-2)*180=540
n-2=540/180=3
n=5
d)
(n-2)*180=1620
n-2=1620/180=9
n=11
n is the number of sides in each case, hence the answer