Answer: Let the original number be x. According to the question we can write as (2/3)x+20x On rearranging x−(2/3)x=20 Now taking the L.C.M od 1 and 3 is 3 (3x−2x)/3=20 x/3=20 Again by transposing x=60 So the original number is 60 Step-by-step explanation: please mark me as brainliest Reply
Answer:
Let the original number be x.
According to the question we can write as (2/3)x+20x
On rearranging x−(2/3)x=20
Now taking the L.C.M od 1 and 3 is 3
(3x−2x)/3=20
x/3=20
Again by transposing x=60
So the original number is 60
Step-by-step explanation:
please mark me as brainliest
Step-by-step explanation:
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