1f 1 is a zero of the polynomial p(x)=ax2-3(a-1)x -1, then find the value of a

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1f 1 is a zero of the polynomial p(x)=ax2-3(a-1)x -1, then find the value of a

1f 1 is a zero of the polynomial p(x)=ax2-3(a-1)x -1, then find the value of a

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Answer:-a-3

Step-by-step explanation:p(1)=ax2-3(a-1)1-1

=2a-3a-3-0

=-a-3