18. Verify 576 is divisible by 2.3.6 and 9?19. Write all the numbers between 100 and 200 which are divisible by 6?20.

18. Verify 576 is divisible by 2.3.6 and 9?
19. Write all the numbers between 100 and 200 which are divisible by 6?
20. Find the value of
3 1 1
4 3 4
21. The product of two numbers is 25. If one of the number is oz. then find the
22. The length of a rectangular field is 12 – mts and its area is 65*
Find its br
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2 thoughts on “18. Verify 576 is divisible by 2.3.6 and 9?<br />19. Write all the numbers between 100 and 200 which are divisible by 6?<br />20.”

18. 6

19. First no. between 100 and 200 that is divisible by 6 is 102

The last no. between 100 and 200 that is divisible by 6 is 198

Now the numbers between 100 and 200 that is divisible by 6:

102,102+6,102+6+6 ,….

So, it forma an AP

a = first term = 102

d = common difference = 6

a_n=198a

n

=198

Formula of nth term = a_n=a+(n-1)da

n

=a+(n−1)d

198=102+(n-1)6198=102+(n−1)6

198-102=(n-1)6198−102=(n−1)6

96=(n-1)696=(n−1)6

\frac{96}{6}=n-1

6

96

=n−1

16=n-116=n−1

17=n17=n

Sum of n terms = s_n=\frac{n}{2}(2a+(n-1)d)s

n

=

2

n

(2a+(n−1)d)

Substitute n =17

s_{17}=\frac{17}{2}(2(102)+(17-1)6)s

17

=

2

17

(2(102)+(17−1)6)

s_{17}=2550s

17

=2550

Hence the sum of integers between 100 and 200 that are divisible by 6 is 2550