15. X number of men can finish a piece of work in 30
days. If there were 6 men more, the work could be
finished in 10 da

15. X number of men can finish a piece of work in 30
days. If there were 6 men more, the work could be
finished in 10 days less. What is the original number
of men?
(a) 10
(b) 11 (c) 12 (d) 15
(e) 13​

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2 thoughts on “15. X number of men can finish a piece of work in 30<br />days. If there were 6 men more, the work could be<br />finished in 10 da”

  1. Given:-

    If . X number of men can finish a piece of work in 30

    days. If there were 6 men more, the work could be

    finished in 10 days less.

    To Find :-

    What is the original number of men?

    Solution :-

    We may observe that the question is going in indirect proportion

    Here,

    30 [tex] \times [/tex] x = 20(6 + x)

    30x = 120 + 20x

    30x – 20x = 120

    10x = 120

    x = 120/10

    x = 12

    [tex]\\[/tex]

    Reply
  2. Required Answer:

    Firstly,

    Let’s understand the relation between the number of men and number of days for doing a piece of work.

    • If there were less number of men, more days will be required to complete the work.
    • They are indirectly proportional to each other. It means, if number of men = x, number of days = m. Then x1.m1 = x2.m2

    Now, Let’s come to the question.

    • X men take 30 days to complete a work.
    • 1 men will takes 30 × X days to complete then. (From the above relation).

    And,

    If there were 6 more men, then number of men now is X + 6. No. of days is 30 – 10 = 20 days.

    • X + 6 men take 20 days to complete.
    • 1 men will take (X + 6)20 days then[tex].[/tex]

    That means,

    ⇒ 30X = (X + 6)20

    ⇒ 30X = 20X + 120

    ⇒ 10X = 120

    ⇒ X = 12 men

    Initially,

    The no. of men were X i.e. 12 (Option C)

    Reply

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