15. X number of men can finish a piece of work in 30days. If there were 6 men more, the work could befinished in 10 days less. What is the original numberof men?(a) 10(b) 11 (c) 12 (d) 15(e) 13 About the author Julia
Given:- If . X number of men can finish a piece of work in 30 days. If there were 6 men more, the work could be finished in 10 days less. To Find :- What is the original number of men? Solution :- We may observe that the question is going in indirect proportion Here, 30 [tex] \times [/tex] x = 20(6 + x) 30x = 120 + 20x 30x – 20x = 120 10x = 120 x = 120/10 x = 12 [tex]\\[/tex] Reply
Required Answer:– Firstly, Let’s understand the relation between the number of men and number of days for doing a piece of work. If there were less number of men, more days will be required to complete the work. They are indirectly proportional to each other. It means, if number of men = x, number of days = m. Then x1.m1 = x2.m2 Now, Let’s come to the question. X men take 30 days to complete a work. 1 men will takes 30 × X days to complete then. (From the above relation). And, If there were 6 more men, then number of men now is X + 6. No. of days is 30 – 10 = 20 days. X + 6 men take 20 days to complete. 1 men will take (X + 6)20 days then[tex].[/tex] That means, ⇒ 30X = (X + 6)20 ⇒ 30X = 20X + 120 ⇒ 10X = 120 ⇒ X = 12 men Initially, The no. of men were X i.e. 12 (Option C) Reply
Given:-
If . X number of men can finish a piece of work in 30
days. If there were 6 men more, the work could be
finished in 10 days less.
To Find :-
What is the original number of men?
Solution :-
We may observe that the question is going in indirect proportion
Here,
30 [tex] \times [/tex] x = 20(6 + x)
30x = 120 + 20x
30x – 20x = 120
10x = 120
x = 120/10
x = 12
[tex]\\[/tex]
Required Answer:–
Firstly,
Let’s understand the relation between the number of men and number of days for doing a piece of work.
Now, Let’s come to the question.
And,
If there were 6 more men, then number of men now is X + 6. No. of days is 30 – 10 = 20 days.
That means,
⇒ 30X = (X + 6)20
⇒ 30X = 20X + 120
⇒ 10X = 120
⇒ X = 12 men
Initially,
The no. of men were X i.e. 12 (Option C)