14. A man is four times as old as his son. After 20 years, he will be twice as old as hisson at that time. Find their present ages. who will give correct answer with explanation I will mark them as BRAINLIST PLEASE ANSWER About the author Eloise
Step-by-step explanation: Let the age of son be x Father’s age = 4x After 20 years, Son’s age = x + 20, Father’s age = 4x + 20 According to question, 2×(x+20) = 4x + 20 => 2x + 40 = 4x + 20 => 2x = 20 => x = 10 years(Son’s age) 4x = 40 years(Father’s Age) Reply
Step-by-step explanation:
Let the age of son be x
Father’s age = 4x
After 20 years,
Son’s age = x + 20, Father’s age = 4x + 20
According to question,
2×(x+20) = 4x + 20
=> 2x + 40 = 4x + 20
=> 2x = 20
=> x = 10 years(Son’s age)
4x = 40 years(Father’s Age)