125(x²yz+xy²z+xyz²) by 5xyz
I want this now only I’m on exam
125(x²yz+xy²z+xyz²) by 5xyz
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125(x²yz+xy²z+xyz²) by 5xyz
I want this now only I’m on exam
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Answer:
The answer is 5(x+y+z).
Step-by-step explanation:
This happens because the denominator cancels the like numerators.
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