12: Two dice are thrown. Let A be the event that the sum of the
points on the faces is 9.let B be the event that at least one

2 thoughts on “12: Two dice are thrown. Let A be the event that the sum of the<br />points on the faces is 9.let B be the event that at least one”

1. Given : Two dice are thrown.

   A be the event that the sum of the points on the faces is 9.

   B be the event that at least one number 6.

   To Find : P(AUB)

   Solution:

   Two dice are thrown.

   hence possible outcomes = 6 * 6 = 36

   P(AUB) = P(A) + P (B) – P ( A∩B)

   A = sum of the points on the faces is 9.

   => A = { ( 3 , 6) , ( 4 , 5) , ( 5 , 4 ) , ( 6 , 3) }

   => n(A) = 4

   B = at least one number 6.

   => B = { (1 , 6) , ( 2 ,6 ) , ( 3 , 6) , ( 4 , 6) , ( 5 , 6) , ( 6 , 6) , ( 6 , 5) , ( 6 , 4) , ( 6 ,3 ) , ( 6 ,2 ) , ( 6 , 1) }

   n(B) = 11

   A∩B means sum of the points on the faces is 9. and at least one number 6.

   => A∩B = { ( 3 , 6) , ( 6 , 3) }

   n ( A∩B) = 2

   n (AUB) = 4 + 11 – 2 = 13

   P(AUB)= = 13/36

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2. Answer:

   Step-by-step explanation:

   Ok

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