11. The circumference of a circular table is 88cm. Find the radius of the table.​

2 thoughts on “11. The circumference of a circular table is 88cm. Find the radius of the table.​”

1. Concept:

   Here, we have to find the radius of the circular table if the circumference is 88 cm . To Find it we will apply the Formula of Circumference of a circle , that is 2πr . By substituting this we will get our Required Value.

   Question:

   • The circumference of a circular table is 88cm. Find the radius of the table.

   Given:

   • Circumference of a circular table = 88 cm

   To Find:

   • Radius of a circular table = ?

   Formula Required:

   • Circumference of a circle = 2πr

   ㅤㅤㅤwhere,

   ㅤㅤㅤRadius = r

   Solution:

   ㅤㅤㅤWe know,

   Circumference of a circular table = 2πr

   ㅤ➟ㅤ88 = 2 × 22/7 × r

   ㅤ➟ㅤ88 = 44/7 × r

   ㅤ➟ㅤ44/7 × r = 88

   ㅤ➟ㅤr = 88 × 7 / 44

   ㅤ➟ㅤr = 616/44

   ㅤ➟ㅤr = 308/22

   ㅤ➟ㅤr = 154/11

   ㅤ➟ㅤr = 14/1

   ㅤ➟ㅤr = 14 cm

   ㅤㅤㅤHence, the radius of a circular table is 14 cm

   HAPPY LEARNING!!!

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2. [tex]{\large{\underline{\underline{\pmb{\sf{Question:}}}}}}[/tex]

   The circumference of a circular table is 88 cm. Find the radius of the table.

   [tex]{\large{\underline{\underline{\pmb{\sf{Required\:Answer:}}}}}}[/tex]

   The radius of the table is 14 cm.

   [tex]{\large{\underline{\underline{\pmb{\sf{Given:}}}}}}[/tex]

   The Question says that there is a circular table, which has 88 cm as its circumference.

   [tex]{\large{\underline{\underline{\pmb{\sf{To\:find:}}}}}}[/tex]

   According to the Question, we need to find the radius of the circular table.

   [tex]{\large{\underline{\underline{\pmb{\sf{Formula\:used:}}}}}}[/tex]

   To find the circumference of the circle, we use the following formula:

   [tex]{:\implies {\boxed{\sf{Circumference_{(circle)} = 2 \pi r}}}}[/tex]

   From this formula, we will find the radius of the circular table, which is our required answer.

   [tex]{\large{\underline{\underline{\pmb{\sf{Solution:}}}}}}[/tex]

   [tex]\sf{:\implies Circumference_{(circle)} = 2 \pi r}[/tex]

   [tex]\sf{:\implies 88 = 2 \times \dfrac{22}{7} \times r}[/tex]

   [tex]\sf{:\implies \dfrac{88}{2} = \dfrac{22}{7} \times r}[/tex]

   [tex]\sf{:\implies 44 = \dfrac{22}{7} \times r}[/tex]

   [tex]\sf{:\implies 44 \times 7 = 22 \times r}[/tex]

   [tex]\sf{:\implies 308 = 22 \times r}[/tex]

   [tex]\sf{:\implies \dfrac{308}{22} = r}[/tex]

   [tex]\sf{:\implies 14 = r}[/tex]

   [tex]\sf{:\implies r = 14}[/tex]

   [tex]\sf{:\implies Radius_{(Circle)} = 14\:cm}[/tex]

   Hence, the radius of the circular table is 14 cm.

   Reply