107. In what time will Rs.1200 earn an interestof Rs.240 at 5%a) 4 yearsb) 3 yearsc) 2 yearsd) 5 years About the author Charlotte

Given: Principal = Rs. 1200 Simple Interest = Rs. 240 Rate = 5 % What To Find: We have to find the time of the following. Formula Needed: [tex]\it SI = \dfrac{P \times R \times T}{100}[/tex] Where, SI = Simple Interest P = Principal R = Rate T = Time Solution: Using the formula, [tex]\sf \implies SI = \dfrac{P \times R \times T}{100}[/tex] Substitute the values, [tex]\sf \implies 240 = \dfrac{1200 \times 5 \times T}{100}[/tex] Cancel the zeros, [tex]\sf \implies 240 = 12 \times 5 \times T[/tex] Multiply 12 by 5, [tex]\sf \implies 240 = 60 \times T[/tex] Take 60 to LHS, [tex]\sf \implies \dfrac{240}{60} = T[/tex] Cancel the zeros, [tex]\sf \implies \dfrac{24}{6} = T[/tex] Divide 24 by 6, [tex]\sf \implies 4 \: years = T[/tex] Final Answer: The time is 4 years that is option A. Reply

Given: Principal = Rs. 1200 Simple Interest = Rs. 240 Rate = 5 % What To Find: We have to find the time of the following. Formula Needed: [tex]\it SI = \dfrac{P \times R \times T}{100}[/tex] Where, SI = Simple Interest P = Principal R = Rate T = Time Solution: Using the formula, [tex]\sf \implies SI = \dfrac{P \times R \times T}{100}[/tex] Substitute the values, [tex]\sf \implies 240 = \dfrac{1200 \times 5 \times T}{100}[/tex] Cancel the zeros, [tex]\sf \implies 240 = 12 \times 5 \times T[/tex] Multiply 12 by 5, [tex]\sf \implies 240 = 60 \times T[/tex] Take 60 to LHS, [tex]\sf \implies \dfrac{240}{60} = T[/tex] Cancel the zeros, [tex]\sf \implies \dfrac{24}{6} = T[/tex] Divide 24 by 6, [tex]\sf \implies 4 \: years = T[/tex] Final Answer: The time is 4 years that is option A. Reply

## Given:

## What To Find:

We have to find the time of the following.

## Formula Needed:

[tex]\it SI = \dfrac{P \times R \times T}{100}[/tex]

Where,

## Solution:

Using the formula,

[tex]\sf \implies SI = \dfrac{P \times R \times T}{100}[/tex]

Substitute the values,

[tex]\sf \implies 240 = \dfrac{1200 \times 5 \times T}{100}[/tex]

Cancel the zeros,

[tex]\sf \implies 240 = 12 \times 5 \times T[/tex]

Multiply 12 by 5,

[tex]\sf \implies 240 = 60 \times T[/tex]

Take 60 to LHS,

[tex]\sf \implies \dfrac{240}{60} = T[/tex]

Cancel the zeros,

[tex]\sf \implies \dfrac{24}{6} = T[/tex]

Divide 24 by 6,

[tex]\sf \implies 4 \: years = T[/tex]

## Final Answer:

The time is 4 years that is option A.

Given:

Principal = Rs. 1200

Simple Interest = Rs. 240

Rate = 5 %

What To Find:

We have to find the time of the following.

Formula Needed:

[tex]\it SI = \dfrac{P \times R \times T}{100}[/tex]

Where,

SI = Simple Interest

P = Principal

R = Rate

T = Time

Solution:

Using the formula,

[tex]\sf \implies SI = \dfrac{P \times R \times T}{100}[/tex]

Substitute the values,

[tex]\sf \implies 240 = \dfrac{1200 \times 5 \times T}{100}[/tex]

Cancel the zeros,

[tex]\sf \implies 240 = 12 \times 5 \times T[/tex]

Multiply 12 by 5,

[tex]\sf \implies 240 = 60 \times T[/tex]

Take 60 to LHS,

[tex]\sf \implies \dfrac{240}{60} = T[/tex]

Cancel the zeros,

[tex]\sf \implies \dfrac{24}{6} = T[/tex]

Divide 24 by 6,

[tex]\sf \implies 4 \: years = T[/tex]

Final Answer:

The time is 4 years that is option A.