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107. In what time will Rs.1200 earn an interest
of Rs.240 at 5%
a) 4 years
b) 3 years
c) 2 years
d) 5 yea

By Charlotte

107. In what time will Rs.1200 earn an interest
of Rs.240 at 5%
a) 4 years
b) 3 years
c) 2 years
d) 5 years​

About the author
Charlotte

3. In a G. P, the product of the first three terms 27/8. The middle term is
(a) 3/2
(b) 2/3
(c) 2/5
​

The radius of Circle A is 7 ft. The radius of Circle B is 3 ft greater than the radius of
Circle A. The radius of Circle C is

2 thoughts on “107. In what time will Rs.1200 earn an interest<br />of Rs.240 at 5%<br />a) 4 years<br />b) 3 years<br />c) 2 years<br />d) 5 yea”

  1. Given:

    • Principal = Rs. 1200
    • Simple Interest = Rs. 240
    • Rate = 5 %

    What To Find:

    We have to find the time of the following.

    Formula Needed:

    [tex]\it SI = \dfrac{P \times R \times T}{100}[/tex]

    Where,

    • SI = Simple Interest
    • P = Principal
    • R = Rate
    • T = Time

    Solution:

    Using the formula,

    [tex]\sf \implies SI = \dfrac{P \times R \times T}{100}[/tex]

    Substitute the values,

    [tex]\sf \implies 240 = \dfrac{1200 \times 5 \times T}{100}[/tex]

    Cancel the zeros,

    [tex]\sf \implies 240 = 12 \times 5 \times T[/tex]

    Multiply 12 by 5,

    [tex]\sf \implies 240 = 60 \times T[/tex]

    Take 60 to LHS,

    [tex]\sf \implies \dfrac{240}{60} = T[/tex]

    Cancel the zeros,

    [tex]\sf \implies \dfrac{24}{6} = T[/tex]

    Divide 24 by 6,

    [tex]\sf \implies 4 \: years = T[/tex]

    Final Answer:

    The time is 4 years that is option A.

    Reply

  2. Given:

    Principal = Rs. 1200

    Simple Interest = Rs. 240

    Rate = 5 %

    What To Find:

    We have to find the time of the following.

    Formula Needed:

    [tex]\it SI = \dfrac{P \times R \times T}{100}[/tex]

    Where,

    SI = Simple Interest

    P = Principal

    R = Rate

    T = Time

    Solution:

    Using the formula,

    [tex]\sf \implies SI = \dfrac{P \times R \times T}{100}[/tex]

    Substitute the values,

    [tex]\sf \implies 240 = \dfrac{1200 \times 5 \times T}{100}[/tex]

    Cancel the zeros,

    [tex]\sf \implies 240 = 12 \times 5 \times T[/tex]

    Multiply 12 by 5,

    [tex]\sf \implies 240 = 60 \times T[/tex]

    Take 60 to LHS,

    [tex]\sf \implies \dfrac{240}{60} = T[/tex]

    Cancel the zeros,

    [tex]\sf \implies \dfrac{24}{6} = T[/tex]

    Divide 24 by 6,

    [tex]\sf \implies 4 \: years = T[/tex]

    Final Answer:

    The time is 4 years that is option A.

    Reply

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