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10. Find the first terms and common difference of an AP, whose t8
=3 and
t12=52
​

By Amaya

10. Find the first terms and common difference of an AP, whose t8
=3 and
t12=52
​

About the author
Amaya

in 3 numbers the mean of the square of first 2 numbers is 26 and the mean of the square of the second and the first is 50 and the

the average of 11 result is 50. If the average of first-six results is 49 and that of last six is 52, find the sixth result​

1 thought on “<br />10. Find the first terms and common difference of an AP, whose t8<br />=3 and<br />t12=52<br />​”

  1. Answer:

    The first term is -331/4

    The common difference is 49/4

    Step-by-step explanation:

    t8 =3 and

    t12=52

    t8 = a + 7d = 3 –(1)

    t12 = a + 11d = 52 –(2)

    from eq.–(1)

    a + 7d = 3

    a = 3 – 7d–(3)

    Put value of a in eq.–(2)

    3 – 7d + 11d = 52

    4d = 52 – 3

    4d = 49

    d = 49/4

    Now put d in eq.–(3)

    a = 3 – 7(49/4)

    = (12 – 343)/4

    = -331/4

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